The time period of a simple pendulum is $2\, sec$. If its length is increased $4$ times, then its period becomes ..... $\sec$
AIPMT 1999, Easy
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(d) $T \propto \sqrt l $
==> $\frac{{{T_1}}}{{{T_2}}} = \sqrt {\frac{{{l_1}}}{{{l_2}}}} $
==> $\frac{2}{{{T_2}}} = \sqrt {\frac{l}{{4l}}} $
==> ${T_2} = 4\,sec$
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