A boy’s catapult is made of rubber cord which is $42\, cm$ long, with $6\, mm$ diameter of cross -section and of negligible mass. The boy keeps a stone weighing $0.02\, kg$ on it and stretches the cord by $20\, cm$ by applying a constant force. When released, the stone flies off with a velocity of $20\, ms^{-1}$. Neglect the change in the area of cross section of the cord while stretched. The Young’s modulus of rubber is closest to
JEE MAIN 2019, Medium
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$Energy\,of\,catapult = \frac{1}{2} \times {\left( {\frac{{\Delta \ell }}{\ell }} \right)^2} \times Y \times A \times \ell $
$ = Kinetic\,energy\,of\,the\,ball = \frac{1}{2}\,m{V^2}$
$Therefore,\frac{1}{2} \times {\left( {\frac{{20}}{{42}}} \right)^2} \times Y \times \pi \times {3^2} \times {10^{ - 6}} \times 42 \times {10^{ - 2}}$
$ = \frac{1}{2} \times 2 \times {10^{ - 2}} \times {\left( {20} \right)^2}$
$Y = 3 \times {10^{6\,}}\,N{m^2}$
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