A cable of resistance $10\,\Omega $ carries electric power from a generator producing $250\, kW$ at $10000\, volt$. The current in the cable is ............. $A$
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(a) Since $P = VI\,$ $ \Rightarrow $ $I = \frac{P}{V} = \frac{{250000}}{{10000}} = 25\,\,A$
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