A capacitance of $2\ μF$ is required in an electrical circuit across a potential difference of $1.0\ kV$. A large number of $1\ μF$ capacitors are available which can withstand a potential difference of not more than $300\ V$. The minimum number of capacitors required to achieve this is
A$1$
B$16$
C$24$
D$32$
JEE MAIN 2017, Medium
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D$32$
d To get a capacitance of $2\, \mu \mathrm{F}$ arrangement of capacitors of capacitance $1\, \mu \mathrm{F}$ as shown in figure $8$ capacitors of $1\, \mu \mathrm{F}$ in parallel with four such branches in series i.e., $32$ such capacitors are required.
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