$\mathrm{U}_{0}=\frac{\mathrm{q}_{0}^{2}}{2 \mathrm{C}}$
after connecting the inductor energy
$\mathrm{U}=\frac{3 \mathrm{U}_{0}}{4}$
So, $\mathrm{q}=\frac{\sqrt{3}}{2} \mathrm{q}_{0}$
and $\mathrm{V} \propto \mathrm{q}$
So, $\mathrm{V}=\frac{\sqrt{3}}{2} \mathrm{V}_{0}$





