c
(c) As $Q = CV, (Q_1)_{max}=10^{-6} × 6 × 10^3 = 6 \ \mu C$
While ($Q_2)_{max}= 3 × 10^{-6} × 4 × 10^3 = 12\ \mu C$
However in series charge is same so maximum charge on $C_2$ will also be $6 \,µC$ (and not $12 \ \mu C$) and potential difference across it $V_2 = 6 / 3 = 2\,kV$ and as in series $V =V_1 + V_2 \,$so $\,V_{max}= 6\,kV + 2\,kV = 8\,kV$