A car is moving on a circular level road of curvature $300\,metres.$ If the coefficient of friction is $0.3$ and acceleration due to gravity is $10\,m/s^2,$ the maximum speed the car can have is ........ $km/hr$ 
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$\mu=\frac{v^{2}}{r g}$

$v^{2}=\mu r g$

$v=\sqrt{\frac{0.3}{10} \times 300 \times 10}$

$v=30 \mathrm{m} / \mathrm{sec}$

$v=30 \times \frac{18}{5}=108 \mathrm{km} / \mathrm{hr}$

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