A car is moving on a horizontal circular track of radius $0.2 \,km$ with a constant speed. If coefficient of friction between tyres of car and road is $0.45$, then speed of car may be ........ $m / s$ [Take $g=10 \,m / s ^2$ ]
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(b)
$\frac{v^2}{r}=\mu g$
$\frac{v^2}{0.2 \times 10^3}=4.5$
$v=\sqrt{900}=30 \,m / s$
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