A car of mass $800 \,kg$ moves on a circular track of radius $40\, m$. If the coefficient of friction is $0.5$, then maximum velocity with which the car can move is ......... $m/s$
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(b)${v_{\max .}} = \sqrt {\mu rg} $$ = \sqrt {0.5 \times 40 \times 9.8} = 14\,m/s$
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