An army vehicle of mass $1000\, kg$ is moving with a velocity of $10 \,m/s$ and is acted upon by a forward force of $1000\, N$ due to the engine and a retarding force of $500 \,N$ due to friction. ........... $m/s$ will be its velocity after $10\, s$
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(c)$v = u + \frac{F}{m}t = 10 + \left( {\frac{{1000 - 500}}{{1000}}} \right) \times 10 = 15\,m/s$
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