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Redox Reactions — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryRedox Reactions3 Marks
Question
A cell is constructed using $\frac{\text{Cu}^{2+}}{\text{Cu}}$ and $\frac{\text{Al}^{3+}}{\text{Al}}$ electrodes.
  1. Identify cathode and anode.
  2. Write the reactions at anode, cathode and net cell reaction.
  3. Calculate $\text{E}^0_\text{cell}$
$\text{E}^0_\frac{\text{Al}^{3+}}{\text{Ag}}=-1.66\text{V}$

$\text{E}^0_\frac{\text{Cu}^{2+}}{\text{Cu}}=+0.34\text{V}$
✓

Answer

It is measured by potentiometer which does not have internal resistance.
  1. 'Al' will act as anode, 'Cu' will act as cathode because reduction potential of $\frac{\text{Cu}^{2+}}{\text{Cu}}$ is higher.
  2.  
  1. $\text{E}^0_\text{cell}=\text{E}^0_\frac{\text{cu}^{2+}}{\text{Cu}}-\text{E}^0_\frac{\text{Al}^{3+}}{\text{Al}}$
$=+0.34\text{V}-(-1.66\text{V})$

$=2.00\text{V}$

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