A charge of ${10^{ - 9}}\,C$ is placed on each of the $64$ identical drops of radius $2\,cm$. They are then combined to form a bigger drop. Find its potential
Medium
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(a) $V = {n^{2/3}}v$ $==>$ $V = {(64)^{2/3}} \times 9 \times {10^9} \times \frac{{{{10}^{ - 9}}}}{{(2 \times {{10}^{ - 2}})}}$
= $7.2 \times {10^3}\,V$
= $7.2 \times {10^3}\,V$
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