A charge particle $A$ of charge $q = 2\,\, C$ has velocity $v = 100\,\, m/s.$ When it passes through point Aand has velocity in the direction shown. The strength of magnetic field at point $B$ due to this moving charge is.......$\mu T$ $(r = 2\,\, m).$
Medium
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$\vec{B}=\frac{\mu_{0}}{4 \pi} \frac{q(\vec{V} \times \vec{r})}{r^{3}}=\frac{\mu_{0}}{4 \pi}=\frac{q V \sin 0}{r^{2}}$
$=10^{-7} \times \frac{2 \times 100 \times \sin 30^{\circ}}{2^{2}}$
$=25 \times 10^{-7} T=2.5 \mu T$
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