A charged particle of mass $m$ and charge $q$ travels on a circular path of radius $r$ that is perpendicular to a magnetic field $B$. The time taken by the particle to complete one revolution is
AIEEE 2005, Easy
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(b) Equating magnetic force to centripetal force,
$\frac{m v^{2}}{r}=q v B \sin 90^{\circ}$
Time to complete one revolution,
$T=\frac{2 \pi r}{v}=\frac{2 \pi m}{q B}$
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