Question
A chemist has one solution containing 50% acid and a second one containing 25% acid. How much of each should be used to make 10 litres of a 40% acid solution?
✓
Answer
Let x litres of 50% solution be mixed with y litres of 25% solution.
Accroding to the given condition,
50% of x + 25% of y = 40% of 10
$\Rightarrow\frac{50}{100}\text{x}+\frac{25}{100}\text{y}=\frac{40}{100}(10)$
50x + 25y = 40(10)
2x + y = 16 ...(i)
Since the amount of each solutions adds to 10 litres,
x + y = 10 ...(ii)
Subtract (ii) from (i).
x = 6
Substituting x = 6 in (ii), we get
y = 4.
Hence, 6 liters of 50% solution is to be mixed with 4 litres of 25% solution.
Accroding to the given condition,
50% of x + 25% of y = 40% of 10
$\Rightarrow\frac{50}{100}\text{x}+\frac{25}{100}\text{y}=\frac{40}{100}(10)$
50x + 25y = 40(10)
2x + y = 16 ...(i)
Since the amount of each solutions adds to 10 litres,
x + y = 10 ...(ii)
Subtract (ii) from (i).
x = 6
Substituting x = 6 in (ii), we get
y = 4.
Hence, 6 liters of 50% solution is to be mixed with 4 litres of 25% solution.
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|
Class
|
100-120
|
120-140
|
140-160
|
160-180
|
180-200
|
|
Frequency
|
10
|
20
|
30
|
15
|
5
|
From the following frequency distribution, prepare the 'More Then Ogive'.
Also find the median.
|
Score
|
Number of candidates
|
|
400-450
|
20
|
|
450-500
|
35
|
|
500-550
|
40
|
|
550-600
|
32
|
|
600-650
|
24
|
|
650-700
|
27
|
|
700-750
|
18
|
|
750-800
|
24
|
|
Total
|
230
|