A coil is placed in $y-z$ plane making an angle of $30^{\circ}$ with $x$ -axis. The current through coil is $I,$ and number of turns are $N$. If a magnetic field of strength $'B'$ is applied in positive $x-$direction, then find the torque experienced by the coil (Radius of coil is $R$) (in $N \cdot m$)
$\left(N=100, I=1 A, R=2\, m, B=\frac{1}{\pi} T\right)$
AIIMS 2019, Medium
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The torque experienced by the coil is calculated as,
$\tau=N L A B \sin \theta$
$=N I\left(\pi R^{2}\right) B \sin 30^{\circ}$
$=100 \times \pi \times(2)^{2} \times \frac{1}{\pi} \times \frac{1}{2}$
$=200 N - m$
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