A coil of $50\, turns$ and $4\,cm$ radius carries $2\,A$ current then magnetic field at its centre is......$mT$
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$\overrightarrow{\mathrm{B}}=\mathrm{N}\left[\frac{\mu_{0} \mathrm{i}}{2 \mathrm{r}}\right]=\frac{50 \times 4 \pi \times 10^{-7} \times 2}{2 \times 4 \times 10^{-2}}=1.57 \times 10^{-3} \mathrm{T}$
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