MCQ
A commercially sold conc. $HCl$ is $35 \% HCl$ by mass. If the density of this commercial acid is $1.46$ $g / mL$, the molarity of this solution is ....$M$
(Atomic mass : $Cl =35.5 \,amu , H =1\, amu$ )
- A$10.2$
- B$12.5$
- ✓$14.0$
- D$18.2$
(Atomic mass : $Cl =35.5 \,amu , H =1\, amu$ )
total mass of solution $=1460 \,g$
mass of $HCl =\frac{35}{100} \times 1460$
moles of $HCl =\frac{35 \times 1460}{100 \times 36.5}$
So molarity $=\frac{35 \times 1460}{100 \times 36.5}=14 \,M$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

($A$) tetranuclear $\left[\mathrm{B}_4 \mathrm{O}_5(\mathrm{OH})_4\right]^{2-}$ unit
($B$) all boron atoms in the same plane
($C$) equal number of $s p^2$ and $s p^3$ hybridized boron atoms
($D$) one terminal hydroxide per boron atom


