A common emitter amplifier is designed with NPN transistor $(\alpha= 0.99 ).$ The input impedance is $1 K \Omega$ and load is $10 k \Omega$. The voltage gain will be
A$9.9$
B$99$
C$990$
D$9900$
[CPMT 1996]
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C$990$
Voltage gain $=\beta \times$ Resistance gain
$ \beta=\frac{\alpha}{1-\alpha}=\frac{0.99}{(1-0.99)}=99 $
$ \text { Resistance gain }=\frac{10 \times 10^3}{10^3}=10 $
$ \Rightarrow \text { Voltage gain }=99 \times 10=990 .$
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