MCQ
A compound $X$, of boron reacts with $\ce{NH_3}$ on heating to give another compound $Y$ which is called inorganic benzene. The compound $X$ can be prepared by treating $\ce{BF_3}$ with Lithium aluminium hydride. The compounds $X$ and $Y$ are represented by the formulas.
  • $ \mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
  • B
    $ \mathrm{~B}_2 \mathrm{O}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
  • C
    $ \mathrm{BF}_3, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
  • D
    $ \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6, \mathrm{~B}_2 \mathrm{H}_6 $

Answer

Correct option: A.
$ \mathrm{B}_2 \mathrm{H}_6, \mathrm{~B}_3 \mathrm{~N}_3 \mathrm{H}_6 $
A compound $X$, of boron reacts with $NH_3$ on heating to give another compound $Y$ which is called inorganic benzene.
$ \ \ \ \ \ \ 3\text{B}_2\text{H}_6+6\text{NH}_3\rightarrow3[\text{BH}_2(\text{NH}_3)_2]^+[\text{BH}^4]^-\\ \ \ \ \ \ \ \ \ \ \ \ \ \text{(x)} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \downarrow \text{heat}\\ \ \ \ \ \ \ \ \ ^\text{Diborane}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2\text{B}_3\text{N}_3\text{H}_6+12\text{H}_2 \\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(Y)}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Borazole/ Inorganic benzene}\\4\text{BF}_3+3\text{LiAlH}_4\xrightarrow{ \ \ \ \ \ \ \ \ \ }2\text{B}_2\text{H}_6+3\text{LiF}+3\text{AIF}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ^\text{(x)}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free