A conducting rod of length 2l is rotating with constant angular s… - Vidyadip

MCQ

A conducting rod of length $2l$ is rotating with constant angular speed $omega$ about its perpendicular bisector. A uniform magnetic field $\overrightarrow B $ exists parallel to the axis of rotation. $The e.m.f.$ induced between two ends of the rod is

A
$B$ $\omega$l2
B
$\frac{1}{2}B\omega {l^2}$
C
$\frac{1}{8}B\omega {l^2}$
✓
$Zero$

✓

Answer

Correct option: D.

$Zero$

d
(d) Potential difference between

$O$ and $A$ is ${V_0} - {V_A} = \frac{1}{2}B{l^2}\omega $

$O$ and $B$ is

${V_0} - {V_B} = \frac{1}{2}B{l^2}\omega $

so ${V_A} - {V_B} = 0$

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