charge $=Q$
radius $=2 a$ (inner)
outer radius $=3 a$
Electric field due to each sphere
$E_{1}=E_{3}=0$ (inside the inner conductor from $O$ to a and from $2 a$ to $3 a$ in conducting shell)
$E_{2}$ and $E_{4}=\frac{K Q}{r^{2}}$
Now,
$d U=0.5 e\left\{E_{2} r^{2} \cdot d r(a \; to \; 2 a)\right\}+E_{4} 2 r^{2} d r\{3 a \; to\; \alpha\}$
$=\frac{5}{12} \frac{Q^{2}}{4 \pi \epsilon_{0} a}$
$=\frac{5}{{12}}\frac{{k{Q^2}}}{a}$

