a
Work done in moving the conductor is,
$W=\int_{0}^{2} F d x$
$=\int_{0}^{2} 3.0 \times 10^{-4} e^{-0.2 x} \times 10 \times 3 d x$
$=9 \times 10^{-3} \int_{0}^{2} e^{-0.2 x} d x$
$=\frac{9 \times 10^{-3}}{0.2}\left[-e^{-0.2 \times 2}+1\right] B=3.0 \times 10^{-4} e^{-0.2 x}$
(By exponential function)
$=\frac{9 \times 10^{-3}}{0.2} \times\left[1-e^{-0.4}\right]$
$=9 \times 10^{-3} \times(0.33)=2.97 \times 10^{-3}\, \mathrm{J}$
Power required to move the conductor is, $P=\frac{W}{t}$
$P=\frac{2.97 \times 10^{-3}}{(0.2) \times 5 \times 10^{-3}}=2.97 \,\mathrm{W}$
