Surface tension $= 75 \times 10^{-3}$ $ N/m $ and $g = 10$ $ m/s^2$:
- A$20$
- B$40$
- ✓$30 $
- D$60$
Surface tension $= 75 \times 10^{-3}$ $ N/m $ and $g = 10$ $ m/s^2$:
$\Rightarrow \frac{2 \times 75 \times 10^{-3}}{0.05 \times 10^{-3}}=10^{3} \times 10 \times h$
$\Rightarrow 3000=10^{3} \times 10 \times h$
$\Rightarrow h=0.3 m=30 \mathrm{cm}$
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Statement $I$ : Acidity of $\alpha$-hydrogens of aldehydes and ketones is responsible for Aldol reaction.
Statement $II$ : Reaction between benzaldehyde and ethanal will $NOT$ give Cross - Aldol product. In the light of above statements, choose the most appropriate answer from the options given below.
($AV$) $\vec{u}_0=\sqrt{2 g h} \hat{x}$ ($B$) $\vec{v}=\sqrt{2 g h}(\hat{x}-\hat{z})$ ($C$) $\theta=60^{\circ}$ ($D$) $d / h_1=2 \sqrt{3}$