A copper rod and a steel rod of equal cross-sections and lengths $(L)$ are joined side by side and connected between two heat baths as shown in the figure
If heat flows through them from $x = 0$ to $x = 2L$ at a steady rate and conductivities of the metals are $K_{cu}$ and $K_{steel}$ $(K_{cu} > K_{steel}),$ then the temperature varies as (convection and radiation are negligible)
Diffcult
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Heat current through the rods is same.
Thus $\Delta \mathrm{T}=\mathrm{i} \mathrm{R}$
$\mathrm{R}=\frac{\mathrm{X}}{\mathrm{K} \mathrm{A}}$
$\therefore \Delta \mathrm{T}=\frac{\mathrm{ix}}{\mathrm{KA}}$
Slope for copper is less than slope for steel $\left(\mathrm{K}_{\mathrm{Cu}}>\mathrm{K}_{\mathrm{Steel}}\right)$
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