A copper solid cube of $60\,\, mm$ side is subjected to a pressure of $2.5 \times 10^7\, Pa$. If the bulk modulus of copper is $1.25 \times 10^{11}\, N/m^2$, the change in the volume of cube is
A$-43.2\, m^3$
B$-43.2\, mm^3$
C$-43.2\, cm^3$
D$-432\, mm^3$
Medium
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B$-43.2\, mm^3$
b $\mathrm{B}=-\frac{\Delta \mathrm{PV}}{\Delta \mathrm{V}} \Rightarrow \Delta \mathrm{V}=-\frac{\Delta \mathrm{PV}}{\mathrm{B}}$
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