A copper solid cube of $60\,\, mm$ side is subjected to a pressure of $2.5 \times 10^7\, Pa$. If the bulk modulus of copper is $1.25 \times 10^{11}\, N/m^2$, the change in the volume of cube is
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$\mathrm{B}=-\frac{\Delta \mathrm{PV}}{\Delta \mathrm{V}} \Rightarrow \Delta \mathrm{V}=-\frac{\Delta \mathrm{PV}}{\mathrm{B}}$
$=-\frac{2.5 \times 10^{7}}{1.25 \times 10^{11}} \times(60)^{3} \mathrm{mm}^{3}=-43.2 \mathrm{mm}^{3}$
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