A cube of edge length $10 \,cm$ is just balanced at the interface of two liquids $A$ and $B$ as shown in figure. If $A$ and $B$ has specific gravity $0.6$ and $0.4$ respectively, then mass of cube is ................ $g$
Medium
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(c)
$m g=F B$ (Buoyant face)
$m g=\left(v_1 \rho_1 g\right)+\left(v_2 \rho_2 g\right)$
$m=\left(v_1 \rho_1+v_2 \rho_2\right) \quad \rho_1=600\,kg / m ^3$
$=480 \times 10^3 \times 10^{-6}\,Kg$
$1\,m =480\,gm$
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