A liquid $X$ of density $3.36\ g/cm^3$ is poured in a $U-$ tube, which contains $Hg$. Another liquid $Y$ is poured in left arm with height $8\ cm$, upper levels of $X$ and $Y$ are same. What is density of $Y$ .......... $g/cc$
Medium
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As shown in figure, in the two arms of a tube pressure remains same on surface $pp'.$ Hence,
$8 \times \rho_{y} \times g+2 \times \rho_{H g} \times g=10 \times \rho_{x} \times g$
$\therefore 8 \rho_{y}+2 \times 13.6=10 \times 3.36$
or $\rho_{y}=\frac{33.6-27.2}{8}=0.8 \mathrm{g} / \mathrm{cc}$
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