d
Volume flow rate is same
So $\pi\left(1 \times 10^{-2}\right)^{2} \times 3$
$=100 \times \pi\left(\frac{0.05 \times 10^{-2}}{2}\right)^{2} \times V$
$\pi \times 10^{-4} \times 3$
$=100 \times \pi \times 1 / 4 \times 25 \times 10^{-8} \times V$
$V=\frac{4 \times 3}{25} \times 100=48$