A current of $0.1\, A$ circulates around a coil of $100$ $turns$ and having a radius equal to $5\,cm$. The magnetic field set up at the centre of the coil is ($\mu_0 = 4\pi \times 10^{-7} weber/amp-metre$)
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(d) $B = \frac{{{\mu _0}}}{{4\pi }}.\frac{{2\pi Ni}}{r} = \frac{{{{10}^{ - 7}} \times 2\pi \times 100 \times 0.1}}{{5 \times {{10}^{ - 2}}}} = 4\pi \times {10^{ - 5}}\,T$
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