A current of $0.1 \,A$ flows through a $25 \,\Omega$ resistor represented by the circuit diagram. The current in $80 \,\Omega$ resistor is ........... $A$
KVPY 2013, Medium
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(c)
Given circuit is
We can redraw the circuit as
Let current through $20 \Omega$ resistor is $I_2$, then
$V_{A B}=0.1(25+15)=I_2 \times 20$
or $I_2=\frac{0.1 \times 40}{20}=0.2 \,A$
So, by Kirchhoff's junction rule, current through $8 \,\Omega$ resistance is $I=0.1+0.2=0.3 \,A$
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