A current of $10\, ampere$ is flowing in a wire of length $1.5\, m$. A force of $15\, N$ acts on it when it is placed in a uniform magnetic field of $2$ $tesla$. The angle between the magnetic field and the direction of the current is.....$^o$
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(a) $F = Bil\sin \theta \Rightarrow \sin \theta = \frac{F}{{Bil}} = \frac{{15}}{{2 \times 10 \times 1.5}} = \frac{1}{2}$ $==>$ $\theta = 30^\circ $
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