In the diagram, $I_1$ , $I_2$ are the strength of the currents in the loop and infinite long straight conductor respectively. $OA = AB = R$ . The net magnetic field at the centre $O$ is zero. Then the ratio of the currents in the loop and the straight conductor is
A$\pi $
B$2\pi $
C$\frac{1}{\pi }$
D$\frac{1}{{2\pi }}$
Medium
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D$\frac{1}{{2\pi }}$
d $\frac{\mu_{0} \mathrm{I}_{1}}{2 \mathrm{R}}=\frac{\mu_{0} \mathrm{I}_{2}}{2 \pi(2 \mathrm{R})}$
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