A potentiometer is used for the comparison of $e.m.f.$ of two cells ${E_1}$ and ${E_2}$. For cell ${E_1}$ the no deflection point is obtained at $20\,cm$ and for ${E_2}$ the no deflection point is obtained at $30\,cm$. The ratio of their $e.m.f.$'s will be
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(a) Ratio will be equal to the ratio of no deflection lengths i.e. $\frac{{{E_1}}}{{{E_2}}} = \frac{{{l_1}}}{{{l_2}}} = \frac{2}{3}$
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