A circular current carrying coil has a radius $R$. The distance from the centre of the coil on the axis where the magnetic induction will be $\frac{1}{8}^{th}$ to its value at the centre of the coil, is
A$\frac{R}{{\sqrt 3 }}$
B$R\sqrt 3 $
C$2\sqrt 3 \,R$
D$\frac{2}{{\sqrt 3 }}R$
Diffcult
Download our app for free and get started
B$R\sqrt 3 $
b (b) $\frac{{{B_{centre}}}}{{{B_{axis}}}} = {\left( {1 + \frac{{{x^2}}}{{{R^2}}}} \right)^{3/2}},$
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
One metre length of wire carries a constant current. The wire is bent to form a circular loop. The magnetic field at the centre of this loop is $B$. The same is now bent to form a circular loop of smaller radius to have four turns in the loop. The magnetic field at the centre of this new loop is
Two straight parallel wires, both carrying $10$ $ampere$ in the same direction attract each other with a force of $1 \times {10^{ - 3}}\,N$. If both currents are doubled, the force of attraction will be
Consider the mass-spectrometer as shown in figure. The electric field between plates is $\vec E\ V/m$ , and the magnetic field in both the velocity selector and in the deflection chamber has magnitude $B$ . Find the radius $'r'$ for a singly charged ion of mass $'m'$ in the deflection chamber
The figure shows three situations when an electron moves with velocity $\vec v$ travels through a uniform magnetic field $\vec B$. In each case, what is the direction of magnetic force on the electron
An electron enters a chamber in which a uniform magnetic field is present as shown below. An electric field of appropriate magnitude is also applied, so that the electron travels undeviated without any change in its speed through the chamber. We are ignoring gravity. Then, the direction of the electric field is
In a region of space, a uniform magnetic field $B$ exists in the $y-$direction.Aproton is fired from the origin, with its initial velocity $v$ making a small angle $\alpha$ with the $y-$ direction in the $yz$ plane. In the subsequent motion of the proton,