MCQ
A circular loop ofradius $0.3\ cm$ lies parallel to amuch bigger circular loop ofradius $20\ cm$. The centre of the small loop is on the axis of the bigger loop. The distance between their centres is $15\ cm$. If a current of $2.0\ A$ flows through the smaller loop, then the flux linked with bigger loop is
  • A
    $6.6 \times 10^{-9}$ $ weber$
  • $9.1 \times 10^{-11} $ $weber$
  • C
    $6.0 \times 10^{-11} $ $weber$
  • D
    $3.3 \times 10^{-11} $ $weber$

Answer

Correct option: B.
$9.1 \times 10^{-11} $ $weber$
b
Aswe know, Magnetic flux, $\phi=B . A$

$\frac{\mu_{0}(2)\left(20 \times 10^{-2}\right)^{2}}{2\left[(0.2)^{2}+(0.15)^{2}\right]} \times \pi\left(0.3 \times 10^{-2}\right)^{2}$

On solving

$=9.216 \times 10^{-11}=9.2 \times 10^{-11}$ $ weber$

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