A die has two faces each with number 1, three faces each with num… - Vidyadip

Question

A die has two faces each with number 1, three faces each with number 2 and one face with number 3. If die is rolled once, determine P(1 or 3)

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Answer

Total number of faces in a die = 6
Number of faces with number 1 = 2
Number of faces with number 3 = 1
$\therefore \;P(1) = \frac{2}{6} = \frac{1}{3},\;P(3) = \frac{1}{6}$
P (1 or 3) = P(1) + P(3) $= \frac{1}{3} + \frac{1}{6} = \frac{{2 + 1}}{6} = \frac{3}{6} = \frac{1}{2}$

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