Question
A disc rotating about its axis from rest, acquires the angular speed $100 \,rev/s$ in $4$ second. The angle rotated by it during these four seconds (in radian) is ...... $\pi$

Answer

(d)

Initial angular speed, $\omega_0=0 rad / s$

Final angular speed, $\omega=100 rps$

$\Rightarrow \omega=100 \times 2 \pi rad$ $\Rightarrow \omega=200 \pi rad / s$

Time, $t=4 s$

From kinematics:

$\omega =\omega_0+\alpha t$

$\Rightarrow 200 \pi=4 \alpha$

$\Rightarrow \alpha=\frac{200 \pi}{4} rad / s ^2$

where, $\alpha$ is angular acceleration.

Also,

$\theta =\omega_0 t+\frac{1}{2} \alpha t^2$

$\Rightarrow \theta =0+\frac{1}{2} \times \frac{200 \pi}{4} \times 16$

$\Rightarrow \theta =400 \pi$

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