$f _{2}=$ frequency heard by driver after reflection from wall
$f_{2}=\left(\frac{v_{s}+v_{c}}{v_{s}}\right) f_{1}=\left(\frac{v_{s}+v_{c}}{v_{s}-v_{c}}\right) f_{0}$
$\frac{f_{2}}{f_{0}}=\frac{v_{s}-v_{c}}{v_{s}+v_{c}}$
$\frac{48}{44}=\frac{v_{s}-v_{c}}{v_{s}+v_{c}}$
$12\left( v _{ s }+ v _{ c }\right)=11\left( v _{ s }- v _{ c }\right)$
$23 v _{ c }= v _{ s }$
$v _{ c }=\frac{ v _{ s }}{23}=\frac{345}{23}=15 m / s$
$=\frac{15 \times 18}{5}=54 km / hr$
$\left[\right.$ Gain in $\left. dB =10 \log _{10}\left(\frac{ P _{0}}{ P _{i}}\right)\right]$
$I.$ The speed of the wave is $4n \times ab$
$II.$ The medium at $a$ will be in the same phase as $d$ after $\frac{4}{{3n}}s$
$III.$ The phase difference between $b$ and $e$ is $\frac{{3\pi }}{2}$
Which of these statements are correct