$I.$ The speed of the wave is $4n \times ab$
$II.$ The medium at $a$ will be in the same phase as $d$ after $\frac{4}{{3n}}s$
$III.$ The phase difference between $b$ and $e$ is $\frac{{3\pi }}{2}$
Which of these statements are correct
Path difference between $b$ and $e$ is $\frac{{3\lambda }}{4}$
So the phase difference =$\frac{{2\pi }}{\lambda } \times $Path difference
= $\frac{{2\pi }}{\lambda }.\frac{{3\lambda }}{4} = \frac{{3\pi }}{2}$
${y_1} = 2a\sin (\omega t - kx)$ and ${y_2} = 2a\sin (\omega t - kx - \theta )$
The amplitude of the medium particle will be