MCQ
A flow of $10^{7}$ electrons per second in a conducting wire constitutes a current of
- A$1.6 \times 10^{12} \;A$
- B$1.6 \times 10^{26} \;A$
- C$1.6 \times 10^{-26} \;A$
- ✓$1.6 \times 10^{-12} \;A$
✓
Answer
Correct option: D.
$1.6 \times 10^{-12} \;A$
d
Flow of electrons, $\frac{n}{t}=10^{7} / sec .$
Flow of electrons, $\frac{n}{t}=10^{7} / sec .$
$(I)=\frac{q}{t}=\frac{n e}{t}=\frac{n}{t} \times e$
$=10^{7} \times\left(1.6 \times 10^{-19}\right)=1.6 \times 10^{-12}\; A$
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