MCQ
A force $\text{F}=-\text{kx}^2(\text{x}\neq0)$ acts on a particle in $X-$direction. Find the work done by the force in displacing the particle from $x = -a$ to $x = 2a.$
  • $\frac{3\text{k}}{2\text{a}}$
  • B
    $\frac{4\text{k}}{\text{a}^2}$
  • C
    $\frac{-3\text{k}}{2\text{a}^2}$
  • D
    $\frac{-9\text{k}}{\text{a}^2}$

Answer

Correct option: A.
$\frac{3\text{k}}{2\text{a}}$

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