A galvanometer has a resistance of $25\, ohm$ and a maximum of $0.01\, A$ current can be passed through it. In order to change it into an ammeter of range $10\, A$, the shunt resistance required is
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(d) ${i_g} = i\frac{S}{{G + S}}$
$ \Rightarrow $ $0.01 = 10\frac{S}{{25 + S}}$
$ \Rightarrow \,\,\,1000S = 25 + S$
$ \Rightarrow $ $S = \frac{{25}}{{999}}\,\Omega $.
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