MCQ
A galvanometer having a resistance $G$ and current $I_g$ flowing in it, produces full scale defection. If $S_1$ is the value of shunt which converts it into an ammeter of range $0-I$ and $S_2$ is the value of shunt for range $0-8I$ . Then the ratio $\frac {S_1}{S_2}$ will be
- ✓$\frac{{8I - {I_g}}}{{I - {I_g}}}$
- B$1$
- C$8$
- D$\frac{1}{2}\left( {\frac{{I - {I_g}}}{{8I - {I_g}}}} \right)$
