MCQ
A galvanometer having coil resistance $10 \ \Omega$ shows a full scale deflection for a current of $3 \mathrm{~mA}$. For it to measure a current of $8 \mathrm{~A}$, the value of the shunt should be:
  • A
     $3 \times 10^{-3}\  \Omega$
  • B
     $4.85 \times 10^{-3} \ \Omega$
  • C
     $3.75 \times 10^{-3} \ \Omega$
  • D
    $2.75 \times 10^{-3} \ \Omega$

Answer

Given $\mathrm{G}=10\  \Omega$

$ \mathrm{I}_{\mathrm{g}}=3 \mathrm{~mA} $

$ \mathrm{I}=8 \mathrm{~A}$

In case of conversion of galvanometer into ammeter.

We have $\mathrm{I}_{\mathrm{g}} \mathrm{G}=\left(\mathrm{I}-\mathrm{I}_{\mathrm{g}}\right) \mathrm{S}$

$ S=\frac{I_g G}{I-I_g} $

$ S=\frac{\left(3 \times 10^{-3}\right) 10}{8-0.003}=3.75 \times 10^{-5} \Omega$

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