MCQ
A gas at $ 27\ ^oC$ has a volume $V$ and pressure $P$. On heating its pressure is doubled and volume becomes three times. The resulting temperature of the gas will be ....... $^oC$
- A$1800$
- B$162$
- ✓$1527$
- D$ 600$
✓
Answer
Correct option: C.
$1527$
c
From ideal gas equation $P V=\neq R T$
From ideal gas equation $P V=\neq R T$
we get $\frac{T_{2}}{T_{1}}=\left(\frac{P_{2}}{P_{1}}\right)\left(\frac{V_{2}}{V_{1}}\right)=\left(\frac{2 P_{1}}{P_{1}}\right)\left(\frac{3 V_{1}}{V_{1}}\right)=6$
$\therefore T_{2}=6 T_{1}=6 \times 300=1800 K=1527^{\circ} \mathrm{C}$
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