MCQ
A group $15$ element, which is a metal and forms a hydride with strongest reducing power among group $15$ hydrides. The element is
- A$Sb$
- B$p$
- C$As$
- D$Bi$
✓
Answer
In group $15\left.\begin{array}{l} N \\ p \end{array}\right] \rightarrow$ Non metal
$\left.\begin{array}{l} As \\ Sb \end{array}\right] \rightarrow$ Metalloid
$Bi ] \rightarrow$ Metal
Hydrides of group $15$ elements are $NH _{3}$
$PH _{3}$
$AsH _{3}$
$SbH _{3}$
$BiH _{3}$
In $NH _{3}$, hydrogen atom gets partial positive charge due to less electronegativity.
But in $BiH _{3},$ hydrogen atom gets partial negative charge because hydrogen is more electronegative than bismuth.
i.e. $BiH _{3}$ is a strong reducing agent than others because we know that $H$ is a strong reducing agent.
$\left.\begin{array}{l} As \\ Sb \end{array}\right] \rightarrow$ Metalloid
$Bi ] \rightarrow$ Metal
Hydrides of group $15$ elements are $NH _{3}$
$PH _{3}$
$AsH _{3}$
$SbH _{3}$
$BiH _{3}$
In $NH _{3}$, hydrogen atom gets partial positive charge due to less electronegativity.
But in $BiH _{3},$ hydrogen atom gets partial negative charge because hydrogen is more electronegative than bismuth.
i.e. $BiH _{3}$ is a strong reducing agent than others because we know that $H$ is a strong reducing agent.
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