A hemispherical bowl of mass $m$ is uniformly charged with charge density $'\sigma '$ . Electric potential due to charge distribution at a point $'A'$ is (which lies at centre of radius as shown).
Medium
Download our app for free and get started
$V = \frac{{{\rm{kQ}}}}{{\rm{R}}} = \frac{{\sigma \times 2\pi {{\rm{R}}^2}}}{{4\pi { \in _0}{\rm{R}}}} = \frac{{\sigma {\rm{R}}}}{{2{ \in _0}}}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Seven identical plates each of area $A$ and successive separation $d$ are arranged as shown in figures. The effective capacitance of the system between $P$ and $Q$ isView Solution
- 2View SolutionWhen a dielectric material is introduced between the plates of a charged condenser then electric field between the plates
- 3For changing the capacitance of a given parallel plate capacitor, a dielectric material of dielectric constant $K$ is used, which has the same area as the plates of the capacitor. The thickness of the dielectric slab is $\frac{3}{4} d$, where $'d'$ is the separation between the plates of parallel plate capacitor. The new capacitance $(C')$ in terms of original capacitance $\left( C _{0}\right)$ is given by the following relationView Solution
- 4Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$.View Solution
Assertion $A$: The potential ( $V$ ) at any axial point, at $2 \mathrm{~m}$ distance ( $r$ ) from the centre of the dipole of dipole moment vector $\vec{P}$ of magnitude, $4 \times 10^{-6} \mathrm{C} \mathrm{m}$, is $\pm 9 \times 10^3 \mathrm{~V}$.
(Take $\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \mathrm{Sl}$ units)
Reason $R$: $V= \pm \frac{2 P}{4 \pi \epsilon_0 r^2}$, where $r$ is the distance of any axial point, situated at $2 \mathrm{~m}$ from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below:
- 5Two capacitors $C_1$ and $C_2 = 2C_1$ are connected in a circuit with a switch between them as shown in the figure. Initially the switch is open and $C_1$ holds charge $Q$. The switch is closed. At steady state, the charge on each capacitor will beView Solution
- 6$n$ the rectangle, shown below, the two corners have charges ${q_1} = - 5\,\mu C$ and ${q_2} = + 2.0\,\mu C$. The work done in moving a charge $ + 3.0\,\mu C$ from $B$ to $A$ is.........$J$ $(1/4\pi {\varepsilon _0} = {10^{10}}\,N{\rm{ - }}{m^2}/{C^2})$View Solution
- 7A point charge $q$ is placed in a cavity in a metal block. If a charge $Q$ is brought outside the metal, then the electric force experienced by $q$ isView Solution
- 8An uncharged parallel plate capacitor having a dielectric of constant $K$ is connected to a similar air-cored parallel capacitor charged to a potential $V$. The two share the charge and the common potential is $V'$. The dielectric constant $K$ isView Solution
- 9Two parallel large thin metal sheets have equal surface charge densities $\left(\sigma=26.4 \times 10^{-12} C / m ^{2}\right)$ of same signs. The electric field between these sheet isView Solution
- 10The equivalent capacitance in the circuit between $A$ and $B$ will be.....$\mu \,F$View Solution
