c
Pressure in the jar $=830 \; mm$ of $Hg$.
Pressure of moisture $=30 \; mm$ of $Hg$.
Pressure of dry gas $=830-30=800 \; mm$ of $Hg$.
Since the volume is constant and the temperature is changing, using the ideal gas equation,
$\frac{ T _{1}}{ P _{1}}=\frac{ T _{2}}{ P _{2}} \Rightarrow \frac{ T _{1}}{800}=\frac{0.99 T _{1}}{ P _{2}} \Rightarrow P _{2}=0.99 \times 800=792 \; mm$ of $Hg$
Therefore, the total pressure $=792+25=817 \; mm$ of $Hg$.